3b^2+b-4=

Solution for 3b^2+b-4= equation:

Simplifying
3b2 + b + -4 = 0

Reorder the terms:
-4 + b + 3b2 = 0

Solving
-4 + b + 3b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-4 + -3b)(1 + -1b) = 0

Subproblem 1
Set the factor '(-4 + -3b)' equal to zero and attempt to solve:

Simplifying
-4 + -3b = 0

Solving
-4 + -3b = 0

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -3b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -3b = 0 + 4
-3b = 0 + 4

Combine like terms: 0 + 4 = 4
-3b = 4

Divide each side by '-3'.
b = -1.333333333

Simplifying
b = -1.333333333
Subproblem 2
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Solution
b = {-1.333333333, 1}